3.1391 \(\int \frac {x^8}{\sqrt {2+x^6}} \, dx\)

Optimal. Leaf size=31 \[ \frac {1}{6} x^3 \sqrt {x^6+2}-\frac {1}{3} \sinh ^{-1}\left (\frac {x^3}{\sqrt {2}}\right ) \]

[Out]

-1/3*arcsinh(1/2*x^3*2^(1/2))+1/6*x^3*(x^6+2)^(1/2)

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Rubi [A]  time = 0.01, antiderivative size = 31, normalized size of antiderivative = 1.00, number of steps used = 3, number of rules used = 3, integrand size = 13, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.231, Rules used = {275, 321, 215} \[ \frac {1}{6} x^3 \sqrt {x^6+2}-\frac {1}{3} \sinh ^{-1}\left (\frac {x^3}{\sqrt {2}}\right ) \]

Antiderivative was successfully verified.

[In]

Int[x^8/Sqrt[2 + x^6],x]

[Out]

(x^3*Sqrt[2 + x^6])/6 - ArcSinh[x^3/Sqrt[2]]/3

Rule 215

Int[1/Sqrt[(a_) + (b_.)*(x_)^2], x_Symbol] :> Simp[ArcSinh[(Rt[b, 2]*x)/Sqrt[a]]/Rt[b, 2], x] /; FreeQ[{a, b},
 x] && GtQ[a, 0] && PosQ[b]

Rule 275

Int[(x_)^(m_.)*((a_) + (b_.)*(x_)^(n_))^(p_), x_Symbol] :> With[{k = GCD[m + 1, n]}, Dist[1/k, Subst[Int[x^((m
 + 1)/k - 1)*(a + b*x^(n/k))^p, x], x, x^k], x] /; k != 1] /; FreeQ[{a, b, p}, x] && IGtQ[n, 0] && IntegerQ[m]

Rule 321

Int[((c_.)*(x_))^(m_)*((a_) + (b_.)*(x_)^(n_))^(p_), x_Symbol] :> Simp[(c^(n - 1)*(c*x)^(m - n + 1)*(a + b*x^n
)^(p + 1))/(b*(m + n*p + 1)), x] - Dist[(a*c^n*(m - n + 1))/(b*(m + n*p + 1)), Int[(c*x)^(m - n)*(a + b*x^n)^p
, x], x] /; FreeQ[{a, b, c, p}, x] && IGtQ[n, 0] && GtQ[m, n - 1] && NeQ[m + n*p + 1, 0] && IntBinomialQ[a, b,
 c, n, m, p, x]

Rubi steps

\begin {align*} \int \frac {x^8}{\sqrt {2+x^6}} \, dx &=\frac {1}{3} \operatorname {Subst}\left (\int \frac {x^2}{\sqrt {2+x^2}} \, dx,x,x^3\right )\\ &=\frac {1}{6} x^3 \sqrt {2+x^6}-\frac {1}{3} \operatorname {Subst}\left (\int \frac {1}{\sqrt {2+x^2}} \, dx,x,x^3\right )\\ &=\frac {1}{6} x^3 \sqrt {2+x^6}-\frac {1}{3} \sinh ^{-1}\left (\frac {x^3}{\sqrt {2}}\right )\\ \end {align*}

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Mathematica [A]  time = 0.01, size = 31, normalized size = 1.00 \[ \frac {1}{6} x^3 \sqrt {x^6+2}-\frac {1}{3} \sinh ^{-1}\left (\frac {x^3}{\sqrt {2}}\right ) \]

Antiderivative was successfully verified.

[In]

Integrate[x^8/Sqrt[2 + x^6],x]

[Out]

(x^3*Sqrt[2 + x^6])/6 - ArcSinh[x^3/Sqrt[2]]/3

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fricas [A]  time = 0.86, size = 29, normalized size = 0.94 \[ \frac {1}{6} \, \sqrt {x^{6} + 2} x^{3} + \frac {1}{3} \, \log \left (-x^{3} + \sqrt {x^{6} + 2}\right ) \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x^8/(x^6+2)^(1/2),x, algorithm="fricas")

[Out]

1/6*sqrt(x^6 + 2)*x^3 + 1/3*log(-x^3 + sqrt(x^6 + 2))

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giac [F]  time = 0.00, size = 0, normalized size = 0.00 \[ \int \frac {x^{8}}{\sqrt {x^{6} + 2}}\,{d x} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x^8/(x^6+2)^(1/2),x, algorithm="giac")

[Out]

integrate(x^8/sqrt(x^6 + 2), x)

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maple [A]  time = 0.14, size = 25, normalized size = 0.81 \[ \frac {\sqrt {x^{6}+2}\, x^{3}}{6}-\frac {\arcsinh \left (\frac {\sqrt {2}\, x^{3}}{2}\right )}{3} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(x^8/(x^6+2)^(1/2),x)

[Out]

-1/3*arcsinh(1/2*2^(1/2)*x^3)+1/6*x^3*(x^6+2)^(1/2)

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maxima [B]  time = 0.99, size = 58, normalized size = 1.87 \[ \frac {\sqrt {x^{6} + 2}}{3 \, x^{3} {\left (\frac {x^{6} + 2}{x^{6}} - 1\right )}} - \frac {1}{6} \, \log \left (\frac {\sqrt {x^{6} + 2}}{x^{3}} + 1\right ) + \frac {1}{6} \, \log \left (\frac {\sqrt {x^{6} + 2}}{x^{3}} - 1\right ) \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x^8/(x^6+2)^(1/2),x, algorithm="maxima")

[Out]

1/3*sqrt(x^6 + 2)/(x^3*((x^6 + 2)/x^6 - 1)) - 1/6*log(sqrt(x^6 + 2)/x^3 + 1) + 1/6*log(sqrt(x^6 + 2)/x^3 - 1)

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mupad [F]  time = 0.00, size = -1, normalized size = -0.03 \[ \int \frac {x^8}{\sqrt {x^6+2}} \,d x \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(x^8/(x^6 + 2)^(1/2),x)

[Out]

int(x^8/(x^6 + 2)^(1/2), x)

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sympy [A]  time = 3.32, size = 39, normalized size = 1.26 \[ \frac {x^{9}}{6 \sqrt {x^{6} + 2}} + \frac {x^{3}}{3 \sqrt {x^{6} + 2}} - \frac {\operatorname {asinh}{\left (\frac {\sqrt {2} x^{3}}{2} \right )}}{3} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x**8/(x**6+2)**(1/2),x)

[Out]

x**9/(6*sqrt(x**6 + 2)) + x**3/(3*sqrt(x**6 + 2)) - asinh(sqrt(2)*x**3/2)/3

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